A line contains the points (-26,-37) and (-32, -61) what is the slope or the line?

Answer :

Step 1. The two points we have are:

[tex]\begin{gathered} (-26,-37) \\ \text{and} \\ (-32,-61) \end{gathered}[/tex]

we will label these points as (x1,y1) and (x2,y2):

[tex]\begin{gathered} x=-26 \\ y_1=-37_{} \\ x_2=-32 \\ y_2=-61 \end{gathered}[/tex]

Step 2. Now that we have labeled the points, we can use the slope formula to find the slope ''m'' of the line:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Substituting the known values:

[tex]m=\frac{-61-(-37)}{-32-(-26)}[/tex]

Step 3. Simplify the signs in the operations.

-(-37) is +37,

and -(-26) is +26:

[tex]m=\frac{-61+37}{-32+26}[/tex]

Step 4. Make the operations:

[tex]m=\frac{-24}{-6}[/tex]

The result of this division is:

[tex]m=4[/tex]

The slope of the line is 4.

Answer:

4