Find the value of x, to the nearest tenth of a unit.

Solution:
Given:
Using the Sine rule;
[tex]\begin{gathered} \frac{sinX}{x}=\frac{sinZ}{z} \\ \frac{sin46.5}{x}=\frac{sin39.4}{7} \\ Cross\text{ multiplying;} \\ x=\frac{7\times sin46.5}{sin39.4} \end{gathered}[/tex]Hence,
[tex]\begin{gathered} x=7.99965 \\ \\ To\text{ the nearest tenth of a unit,} \\ x=8.0\text{ units} \end{gathered}[/tex]Therefore, to the nearest tenth, x = 8.0 units