Solution
For this case we have the following points:
(0,1) and (-3,3)
We can find the slope with this formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{3-1}{-3-0}=-\frac{2}{3}[/tex]
And we can find the intercept like this:
3 = -2/3 *(-3)+b
Solving for b we got:
b= 3-2=1
Then the equation would be:
y= -2/3x +1
