Given
[tex]3x+4y=10[/tex]The equation represents a line on the plane. In general, any line on the plane is determined by two points on it; therefore, we need two find two points that satisfy the given equation, draw them on the plane and cross them using a straight line.
[tex]\begin{gathered} x=0 \\ \Rightarrow4y=10 \\ \Rightarrow y=\frac{10}{4}=\frac{5}{2} \\ \Rightarrow(0,\frac{5}{2}) \\ x=2 \\ \Rightarrow3\cdot2+4y=10 \\ \Rightarrow6+4y=10 \\ \Rightarrow4y=4 \\ \Rightarrow y=1 \\ \Rightarrow(2,1) \end{gathered}[/tex]Plot (0,5/2), (2,1) and cross them using a line, as shown below
