As 20 ft ladder reaches a window 18 ft high. How far is the foot of the ladder from the base of the building? Round your answer to the nearest tenth.

Answer :

11We are given a problem that can be exemplified in the following diagram:

Since the ladder, the wall and the floor form a right triangle we can use the Pythagorean theorem:

[tex]h^{2^{}}=a^2+b^2[/tex]

Where

[tex]\begin{gathered} h=\text{hypotenuse} \\ a=\text{height} \\ b=x \end{gathered}[/tex]

In this case, the hypotenuse is the length of the ladder and the height is the height of the window. Replacing the known values:

[tex](20)^2=(18)^2+b^2[/tex]

Solving the square:

[tex]400=325+b^2[/tex]

Now we solve for "b", first by subtracting 325 to both sides:

[tex]400-325=b^2[/tex]

Solving the operation:

[tex]75=b^2[/tex]

Taking square root to both sides:

[tex]\sqrt[]{75}=b[/tex]

Solving the square root:

[tex]8.7=b[/tex]

Therefore, the foot of the ladder is 8.7 feet from the building.

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