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Enter an equation in point-slope form for the line. Slope is -6 and (1,7) is on the line. The equation of the line in point slope form is:

Answer :

The point slope form of a straight line is given as,

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(7)=-6(x-1) \\ y-7=-6x+6 \\ y+6x=7+6 \\ y+6x=13 \end{gathered}[/tex]

Hence, the equation for the straight line is ,

[tex]y+6x=13[/tex]

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