Solve for x. 16/7x 4x+4/8x-3 X= (Type an integer or a simplified fraction. Use a comma to separate answers as needed.)

EXPLANATION
Considdering the given triangle, we can assevere by the Triangle Proportionality Theorem that there are two similar triangles, and therefore the following relationship is fullfiled:
[tex]\frac{16}{7x}=\frac{4x+4}{8x-3}[/tex]Multiplying both sides by 7x:
[tex]16=7x(4x+4)/(8x-3)[/tex]Multiplying both sudes by 8x-3:
[tex]16(8x-3)=7x(4x+4)[/tex]Applying the distributive property:
128x - 48 = 28x^2 + 28x
Subtracting -(28x^2 +28x) to both sides:
128x - 48 - 28x^2 - 28x = 0
Adding and rearranging terms:
-28x^2 +100x - 48
Solving with the quadratic formula:
[tex]x_1,x_2=\frac{-100\pm\sqrt[]{100^2-4(-28)(-48)}}{2\cdot-28}[/tex]Simplifying:
[tex]x_1,x_2=\frac{-100\pm68}{-56}[/tex]The roots are x_1= 4/7 and x_2 = 3
Just one is the valid option, so considering x=4/7 and replacing in the given equation:
7*4/7 = 4
8* 4/7 - 3 = 11/7
Now, trying with x=3:
7*3 = 21
8*3 -3 = 21 (This is not a viable solution because the Hypotenuse can not be the same as the adjacent leg, so the solution is x=4/7.
The answer is x=4/7