Answer :
Given:
[tex]\begin{gathered} 2x(x+3)=4 \\ (x+1)^2=0 \\ (x+1)^2=(x-4)^2 \\ 3x(2x+5)=0 \end{gathered}[/tex]Required:
To write the given equations in standard form.
Explanation:
Consider
[tex]\begin{gathered} 2x(x+3)=4 \\ 2x^2+6x=4 \\ 2x^2+6x-4=0 \\ \\ (x+1)^2=0 \\ x^2+2x+1=0 \\ \\ (x+1)^2=(x-4)^2 \\ x^2+2x+1=x^2-8x+16 \\ x^2+2x+1-x^2+8x-16=0 \\ 10x-15=0 \\ \\ 3x(2x+5)=0 \\ 6x^2+15x=0 \end{gathered}[/tex]Final Answer:
[tex]\begin{gathered} 6)2x^2+6x-4=0 \\ \\ 7)x^2+2x+1=0 \\ \\ 8)10x-15=0 \\ \\ 9)6x^2+15x=0 \end{gathered}[/tex]