Given:
Distance walked = 15 m south
Then the dg now walked 7 m east before stopping.
Let's find the displacement.
The figure below represents this situation:
The displacement can be said to be the shortest distance from the final position to the ending position.
To find the displacement here, apply Pythagorean theorem:
[tex]d=\sqrt[]{a^2+b^2}[/tex]Where:
a = 15 m
b = 7 m
Thus, we have:
[tex]\begin{gathered} d=\sqrt[]{15^2+7^2} \\ \\ d=\sqrt[]{225+49} \\ \\ d=\sqrt[]{274} \\ \\ d=16.55\text{ m} \end{gathered}[/tex]Therefore, the displacement is 16.55 m.
ANSWER:
16.55 m
