Answer :
Given:
The charge is q1 = -13.37 micro Coulombs
The charge q2 = -20.51 micro Coulombs
The distance between them is 16.26 cm =0.1626 m
To find the electric potential energy.
Explanation:
The potential energy can be calculated by the formula
[tex]U=\frac{kq1q2}{r}[/tex]Here, k is a constant whose value is
[tex]k=9\times10^9\text{ N m}^2\text{ /C}^2[/tex]On substituting the values, the potential energy will be
[tex]\begin{gathered} U=\frac{9\times10^9\times13.37\times10^{-6}\times20.51\times10^{-6}}{0.1626} \\ =\text{ 15.18 J} \end{gathered}[/tex]The electric potential energy is 15.18 J