Not sure on how to do this. Could really use some help. (It says there is 2 parts to the question not sure if there is but I’m assuming it’s after the 1st part is answered.)


The cone shown is oblique. The formula to find the volume of an oblique cone and a right cone is the same. That formula is:
[tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ \text{ Where} \\ V\text{ is the volume} \\ r\text{ is the radius of the base} \\ h\text{ is the height} \end{gathered}[/tex]In this case, we have:
[tex]\begin{gathered} r=\frac{\text{ Diameter}}{2}=\frac{10ft}{2}=5ft \\ h=3ft \end{gathered}[/tex][tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ V=\frac{1}{3}\pi(5ft)^2(3ft) \\ V=\frac{1}{3}\pi(25ft^2)(3ft) \\ V=\pi(25ft^3) \\ V=25\pi ft^3 \end{gathered}[/tex]Using a calculator, we multiply 25 by π and round to the nearest whole number.
[tex]\begin{gathered} 25\cdot\pi\approx79 \\ V\approx79ft^3 \\ \text{ The symbol }\approx\text{ is read 'approximately'.} \end{gathered}[/tex]AnswerPart 1. The volume of the cone in terms of π is 25π cubic ft.
Part 2. The volume rounded to the nearest cubic foot is about 79 cubic ft.