find the value of n if(9 y - 8) + (y + 5) is equivalent to (n y - 3)?

Answer :

[tex](9y-8)+(y+5)=(ny-3)[/tex]

First we need to simplify the expression

[tex]10y-3=ny-3[/tex]

then we sum the terms with y

[tex]\begin{gathered} 10y-ny=3-3 \\ \end{gathered}[/tex][tex]y(10-n)=0[/tex]

then we need to clear n

[tex]\begin{gathered} 10-n=0 \\ n=10 \end{gathered}[/tex]

the value of n=0