Answer:
• Area of sector = 157 mm^2
,
• Area of triangle = 140 mm^2
,
• Area of segment = 17 mm^2
Explanation:
The area of the sector is given as:
[tex]\begin{gathered} A_s=\frac{\theta}{360}\pi r^2 \\ \\ =\frac{45}{360}(20^2)\pi \\ \\ =157mm^2 \end{gathered}[/tex]
The area of the triangle is:
[tex]\begin{gathered} A_t=\frac{1}{2}(base\times height) \\ \\ =\frac{1}{2}\times20\times14=140mm^2 \end{gathered}[/tex]
Area of the segment is given as:
[tex]\begin{gathered} A=A_s-A_t \\ \\ =157mm^2-140mm^2=17mm^2 \end{gathered}[/tex]
