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Find the equation in slope-intercept form that describes a line through (4, –2) with slope –3Question 2 options:a) y = –3x – 2b) y = –3x + 10c) y = –3x + 4d) y = –3x

Answer :

ANSWER :

The answer is b. y = -3x + 10

EXPLANATION :

The point-slope formula is :

[tex]y-y_1=m(x-x_1)[/tex]

Where m = slope and (x1, y1) is a point on the line.

From the problem, the slope is m = -3 and the point is (4, -2)

Using the formula above :

[tex]\begin{gathered} y-(-2)=-3(x-4) \\ y+2=-3x+12 \\ y=-3x+12-2 \\ y=-3x+10 \end{gathered}[/tex]

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