[tex]\begin{gathered} \text{The base = a} \\ \text{the expoent = c} \\ \text{The result is a}^c\text{ = b} \end{gathered}[/tex]
Explanation:[tex]\begin{gathered} \text{Given:} \\ \log ^{}_ab\text{ = c} \\ To\text{ be converted to expoential form} \end{gathered}[/tex]
The conversion:
[tex]\begin{gathered} \log _b(x)\text{ = y} \\ b^y\text{ = x} \end{gathered}[/tex]
Applying the principle to the given logarithm equation:
[tex]\begin{gathered} In\text{ exponential form, }\log ^{}_ab\text{ = c} \\ \text{becomes:} \\ a^c\text{ = b} \end{gathered}[/tex]
[tex]\begin{gathered} \text{The base = a} \\ \text{the expoent = c} \\ \text{The result is a}^c\text{ = b} \end{gathered}[/tex]
