Answer :
Explanation
We are required to determine the equation of the line with the given information below:
[tex]\begin{gathered} (x_1,y_1)=(-8,0) \\ (x_2,y_2)=(-8,6) \end{gathered}[/tex]We know that the equation of a line is given as:
[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]Therefore, we have:
[tex]\begin{gathered} \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \frac{y-0}{x-(-8)}=\frac{6-0}{-8-(-8)} \\ \frac{y}{x+8}=\frac{6}{0} \\ \text{ Cross multiply} \\ 6(x+8)=0 \\ \text{ Divide both sides by 6} \\ \frac{6(x+8)}{6}=\frac{0}{6} \\ x+8=0 \\ x=0-8 \\ x=-8 \end{gathered}[/tex]Hence, the equation of the line is:
[tex]x=-8[/tex]