SOLUTION:
Final answer for 2c
[tex]\begin{gathered} \text{when the bowl has zero table spoons of sugar,} \\ y=mx+c \\ c=350 \\ m=\text{ }\frac{520-350}{15-0} \\ m=1.485 \\ y=\text{ 11.33x + 350} \\ \text{where y is total weight} \\ \text{and x is table spoons of sugar} \\ \end{gathered}[/tex]
Final answer for 2d
Point D answers the question in 2b
[tex]\begin{gathered} y=\text{ 1.485x + 350} \\ y=\text{ 600g} \\ 600\text{ = 11.33x + 350} \\ x=\text{ }\frac{600-350}{11.33} \\ x=22\text{ tablespoons} \end{gathered}[/tex]
