Answer :
SOLUTION
Length = L
Width = W
Perimeter = P
[tex]L\text{ = 2W + 1}[/tex][tex]P\text{ = 2 (L + W)}[/tex][tex]\begin{gathered} P\text{ = 2L + 2W = 92} \\ 2(2W\text{ + 1) + 2W = 92} \\ 4W\text{ + 2 + 2W = 92} \\ 6W+2=92^{} \\ 6W\text{ = 92 - 2} \\ 6W\text{ = 90} \\ W\text{ = }\frac{90}{6} \\ W\text{ = 15 cm} \end{gathered}[/tex][tex]\begin{gathered} L\text{ = 2W + 1} \\ L\text{ = 2(15) + 1} \\ L\text{ = 30 + 1} \\ L\text{ = 31 cm} \end{gathered}[/tex]CONCLUSION:
The length of the rectangle is 31 cm and The width is 15 cm.