Answer :
Given,
The distance between the charges is r=5×10⁻² m
From Coulomb's law, the force between two charges is given by,
[tex]F_e=\frac{kq_1q_2}{r^2}[/tex]Where k is the coulomb's constant, q₁ and q₂ are the charges.
The magnitude of the charge of proton and electron is q=1.6×10⁻¹⁹ C
Thus the force between the two electrons and two protons is,
[tex]\begin{gathered} F_e=\frac{9\times10^{-9}\times1.6\times10^{-19}\times1.6\times10^{-19}}{(5\times10^{-2})^2} \\ =9.22\times10^{-26}\text{ N} \end{gathered}[/tex]Thus the force between two electrons and two protons respectively is 9.22×10⁻²⁶ N