1.A plastic lens has index of refraction n=1.4. If the front of the lens has radius of 1.3 m and the rear of the lens has radius of -0.9 m, what is the refractive power of the lens?1. 0.75 diopters2. 1.5 diopters3. 1.9 diopters4. -0.14 diopters

Answer :

Given:

n = 1.4

radius of the front = 1.3 m

radius of the rear = -0.9 m

Let's find the refractive power of the lens.

To find the refractive power of the lens, apply the formula:

[tex]\frac{1}{f}=(n-1)(\frac{1}{R_1}-\frac{1}{R_2})[/tex]

Thus, we have:

[tex]\begin{gathered} \frac{1}{f}=(1.4-1)(\frac{1}{1.3}-(-\frac{1}{0.9})) \\ \\ \frac{1}{f}=(0.4)(\frac{1}{1.3}+\frac{1}{0.9}) \\ \\ \frac{1}{f}=(0.4)(\frac{0.9+1.3}{1.17}) \\ \\ \frac{1}{f}=(0.4)(\frac{2.2}{1.17}) \\ \\ \frac{1}{f}=0.75 \end{gathered}[/tex]

Therefore, the refractive power of the lens is 0.75 diopters

• ANSWER

1. 0.75 diopters