We have to solve for y:
[tex]\begin{gathered} 1282=23^y+2 \\ 23^y=1282-2 \\ 23^y=1280 \\ \log_{23}(23^y)=\log_{23}(1280) \\ y=\log_{23}(1280) \end{gathered}[/tex]
We can express the solution in terms of a logarithm with base 23 as y = log₂₃(1280).
The approximated value is:
[tex]y=\log_{23}(1280)\approx2.2818[/tex]
Answer:
Exact solution: y = log₂₃(1280)
Approximate solution: y ≈ 2.2818
