The Solution.
By Trigonometrical Ratios, we have,
SOH, CAH, TOA
Where S
Where in the case at hand,
H = 11
To find the value of x in the given problem,
Taking 25 degrees as our angle of interest, we have,
[tex]\begin{gathered} \cos 25=\frac{Adj}{Hyp}=\frac{x}{11} \\ \\ \cos 25=\frac{x}{11} \\ \text{Cross multiplying, we get} \\ x=11\cos 25 \end{gathered}[/tex]
One of the required expressions is:
[tex]x=11\cos 25^o[/tex]
Similarly, taking 65 degrees as the angle of interest, we have
[tex]\begin{gathered} \sin 65=\frac{opp}{Hyp}=\frac{x}{11} \\ \\ \sin 65=\frac{x}{11} \\ \text{Cross multiplying, we get} \\ x=11\sin 65 \end{gathered}[/tex]
The other required expression for finding x is:
[tex]x=11\sin 65^o[/tex]
The correct answers are;
x = 11 sin 65 degrees
x = 11 cos25 degrees
