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show that point A is equidistant from the endpoints of segment BC

Answer :

Solution

for this case we can solve the question with the following operations:

[tex]AB=\sqrt[]{(0-8)^2+(-7-7)^2}=\sqrt[]{260}[/tex]

And similar:

[tex]AC=\sqrt[]{(-8-8)^2+(-5+7)^2}=\sqrt[]{260}[/tex]

Then since AB = AC we can conclude that A is equidistant from the endpoints of the segment BC

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