Answer:
[tex]B.\text{mStep-by-step explanation:
To solve the triangle use the sine law, which is represented by the following equation:
[tex]\begin{gathered} \frac{a}{sinA}=\frac{c}{sinC} \\ \end{gathered}[/tex]Therefore, for the given triangle:
[tex]\begin{gathered} \frac{37}{sin(105)}=\frac{18}{sin(C)} \\ sin(C)=\frac{18*sin(105)}{37} \\ C=\sin^{-1}(\frac{18*sin(105)}{37}) \\ C=28° \end{gathered}[/tex]For angle B, remember that all the intern angles of a triangle must add up to 180 degrees, then;
[tex]\begin{gathered} B=180-105-28 \\ B=47° \end{gathered}[/tex]Now, for side b:
[tex]\begin{gathered} \frac{b}{sin47}=\frac{37}{sin105} \\ b=\frac{37*sin47}{sin105} \\ b=28 \end{gathered}[/tex]Hence, the answer is B.