Find the equation of the straight line that passes through the points -3, -5 and 2, -11. First, what is the slope?

From the given question
There are given that the two points:
[tex](-3,\text{ -5) and (2, -11)}[/tex]Now,
(a)
For finding the slope, use the slope formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Then,
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-11_{}-(-5)_{}}{2_{}-(-3)_{}} \\ m=\frac{-11+5}{2+3} \\ m=-\frac{6}{5} \end{gathered}[/tex]Hence, the slope of the given line is shown below:
[tex]m=-\frac{6}{5}[/tex]