Answer :
At STP (standard temperature and pressure, T = 273K and P = 1 atm), a mol of gas will have a volume of 22.4 Liters, so if we have 57.1 Liters of CO2, we will have:
22.4 L = 1 mol
57.1 L = x moles of CO2
x = 2.5 moles of CO2 in 57.1 L at STP
At STP (standard temperature and pressure, T = 273K and P = 1 atm), a mol of gas will have a volume of 22.4 Liters, so if we have 57.1 Liters of CO2, we will have:
22.4 L = 1 mol
57.1 L = x moles of CO2
x = 2.5 moles of CO2 in 57.1 L at STP