Explanation:
The equation is given below as
[tex]8\sin\theta-8=4\sqrt{3}-8[/tex]
Step 1:
Collect similar terms, we will have
[tex]\begin{gathered} 8\sin(\theta)-8=4\sqrt{3}-8 \\ 8\sin\theta=4\sqrt{3} \end{gathered}[/tex]
Step 2:
Divide both sides by 8
[tex]\begin{gathered} \frac{8\sin\theta}{8}=\frac{4\sqrt{3}}{8} \\ sin\theta=\frac{\sqrt{3}}{2} \\ \theta=\sin^{-1}(\frac{\sqrt{3}}{2}) \\ \theta=\frac{\pi}{3},\frac{2\pi}{3} \end{gathered}[/tex]
Hence,
The final answer is
[tex]\theta=\frac{\pi}{3},\frac{2\pi}{3}[/tex]
