Given the rhombus BCDE, angle EBC=48° and ED=13 Find angle BFC

Answer:
d) 90 degree
Explanation:
Note the below properties of a rhombus;
*Diagonals bisect the angles of a rhombus
*In a rhombus, diagonals bisect each other at right angles
From the second statement, we can deduce that the below angles are right angles, that is, they are equal to 90 degrees;
[tex]\begin{gathered} \angle BFC \\ \angle\text{BFE} \\ \angle\text{CFD} \\ \angle\text{EFD} \end{gathered}[/tex]As seen above, angle BFC is a right angle, that is, it is 90 degrees