The translation < -2,5 > maps J onto J'. If the coordinates of J are (7, -3),what are the coordinates of J'?

Answer:
The coordinates of J' is;
[tex]J^{\prime}(5,2)[/tex]Explanation:
Given the coordinate of J;
[tex]J(7,-3)[/tex]And the translation;
[tex]<-2,5>[/tex]that maps J onto J'.
So, the coordinates of J' will be;
[tex]\begin{gathered} J(x,y)\rightarrow J^{\prime}(x-2,y+5) \\ J(7,-3)\rightarrow J^{\prime}(7-2,-3+5) \\ J(7,-3)\rightarrow J^{\prime}(5,2) \end{gathered}[/tex]Therefore, the coordinates of J' is;
[tex]J^{\prime}(5,2)[/tex]