Answer :
Question: Find the solution to the system of equations. y=x+2 and 4x+2y=16
[tex]\begin{gathered} y=x+2\ldots\ldots(1) \\ 4x+2y=16\ldots\text{.}(2) \end{gathered}[/tex]Step 1: Substitute equation (1) in equation (2)
[tex]\begin{gathered} 4x+2y=16 \\ 4x+2(x+2)=16 \\ 4x+2x+4=16 \\ 6x+4=16 \end{gathered}[/tex]Subtract 4 from both sides of the equation
[tex]\begin{gathered} 6x+4=16 \\ 6x+4-4=16-4 \\ 6x=12 \\ \text{divide both sides by 6} \\ \frac{6x}{6}=\frac{12}{6} \\ x=2 \end{gathered}[/tex]Step 2: Substitute x=2 in equation (1)
[tex]\begin{gathered} y=x+2 \\ y=2+2 \\ y=4 \end{gathered}[/tex]Hence,
x = 2, y = 4