Multiply 7 by 11 and 11 by 7:
[tex]\begin{gathered} \frac{5}{7}\cdot\frac{1}{11}=\frac{5}{77} \\ \frac{8}{11}\cdot\frac{1}{7}=\frac{8}{77} \end{gathered}[/tex]
As you can see if you have two number divide for the same amount, the greater will be the one with the largest numerator, For example:
[tex]\begin{gathered} \frac{8}{4}=2 \\ \frac{12}{4}=3 \end{gathered}[/tex]
Therefore, we can conclude:
[tex]\frac{5}{7}<\frac{8}{7}[/tex]
