Answered

have 154.3 L of gas held at 27 degrees Celsius and a pressure my instruments cannot measure. I change the pressure to 1.5 atm, and the temperature rises to 40.0 degrees Celsíus, while the volume decreases to 50.0 L. What was the original pressure?

Answer :

Answer

P1 = 0.466 atm

Explanation

Given:

Initial volume (V1) = 154.3 L

Final volume (V2) = 50.0 L

Initial Temperature (T1) = 27 °C = 300 K

Final Temperature (T2) = 40.0 °C = 313 K

Initial pressure (P1) = ?

Final pressure (P2) = 1.5 atm

Required: Initial pressure (P1)

Solution

To solve this problem, we will use combined gas law:

[tex]\frac{P_1V_1}{T_1}\text{ = }\frac{P_2V_2}{T_2}[/tex]

Re-arrange:

P1 = (P2V2T1)/T2V1

P1 = (1.5 x 50.0 x 300)/(313 x 154.3)

P1 = 0.466 atm

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