Solution:
Given a straight line graph;
Two points on the line are given as;
[tex](1,1),(4,-2)[/tex]
The slope m, of a line is;
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \\ Where; \\ x_1=1,y_1=1,x_2=4,y_2=-2 \end{gathered}[/tex][tex]\begin{gathered} m=\frac{-2-1}{4-1} \\ \\ m=-\frac{3}{3} \\ m=-1 \end{gathered}[/tex]
Thus, the point-slope equation of a line is;
[tex]y-y_1=m(x-x_1)[/tex]
Thus, the slope-intercept equation of line is;
[tex]\begin{gathered} y-1=-1(x-1) \\ \\ y=1-x+1 \\ \\ y=2-x \end{gathered}[/tex]
ANSWER:
[tex]y=2-x[/tex]
