The number of bacteria in a petri dish on the first daywas 252 cells. If the number of bacteria increase at arate of 57% per day, how many bacteria cells will therebe after 7 days?y = 252(0.57|) ²What number will you fill in for a to solve the equation?7y=

Answer :

Answer:

[tex]\begin{gathered} y=252*1.57^x \\ y=5925\text{ cells} \end{gathered}[/tex]

Step-by-step explanation:

The exponential function is represented by the following equation:

[tex]y=ab^x[/tex]

where a is the initial amount and b is the change factor per unit time, therefore if it creases by 57% per day and the initial amount was 252 cells:

[tex]y=252*1.57^x[/tex]

To determine the population after 7 days, substitute x=7:

[tex]\begin{gathered} y=252*1.57^7 \\ y=5925\text{ cells} \end{gathered}[/tex]