please help me out.thank you

Answer :

[tex]y(he+b)=d+z[/tex]

solve for y by dividing both sides by (he+b)

[tex]\begin{gathered} y\frac{\mleft(he+b\mright)}{\mleft(he+b\mright)}=\frac{d+z}{\mleft(he+b\mright)} \\ y=\frac{d+z}{(he+b)} \end{gathered}[/tex]

to solve for e start by dividing by y on both sides

[tex]\begin{gathered} \frac{y(he+b)}{y}=\frac{d+z}{y} \\ he+b=\frac{d+z}{y} \end{gathered}[/tex]

continue by substracting b on both sides

[tex]\begin{gathered} he+b-b=\frac{d+z}{y}-b \\ he=\frac{d+z}{y}-b \end{gathered}[/tex]

divide by h on both sides to solve for e

[tex]\begin{gathered} \frac{he}{h}=\frac{1}{h}\cdot(\frac{d+z}{y}-b) \\ e=\frac{d+z}{hy}-\frac{b}{h} \end{gathered}[/tex]

ANSWER

[tex]y=\frac{d+z}{(he+b)}[/tex]

[tex]e=\frac{d+z}{hy}-\frac{b}{h}[/tex]

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