a person has a balloon of gas as 64 psi. The volume of the balloon is 6.958L. If the volume of the balloon is reduced to 3L, what will the new pressure be in psi?

To solve this question, we will use Boyle's law that states that "the pressure of a given mass of gas is inversely proportional to the volume provided that the temperature is constant". Mathematically;

[tex]\begin{gathered} P\alpha\frac{1}{V} \\ P=\frac{k}{V} \\ k=P_1V_1=P_2V_2 \end{gathered}[/tex]

• P₁ and P₂ are the, initial ,and, final pressure, of the gas

,

• V₁ and V₂ are the ,initial, and, final volume ,of the gas

Given the following parameters:

P₁ = 64psi

V₁ = 6.958L

V₂ = 3L

Required

New pressure of the gas P₂

Substitute the given parameters into the formula;

[tex]\begin{gathered} P_2=\frac{P_1V_1}{V_2} \\ P_2=\frac{64psi\times6.958\cancel{L}}{3\cancel{L}} \\ P_2=\frac{445.312}{3}\text{psi} \\ P_2=148.44\text{psi} \end{gathered}[/tex]

Therefore the new pressure of the gas in psi is 148.44psi