Given
The decay model for the amount of carbon-14 present after t years is,
[tex]A=16e^{-0.000121t}[/tex]
To find the number of carbon-14 present in 9705 years.
Explanation:
It is given that,
[tex]A=16e^{-0.000121t}[/tex]
Then, for t=9705,
[tex]\begin{gathered} A=16e^{-0.000121\times9705} \\ =16\times0.3090 \\ =4.9445 \\ =5(Rounded\text{ to the nearest whole number}) \end{gathered}[/tex]
Hence, the amount of carbon-14 present in 9705 years is 5grams.
