Given:
[tex]x^2+8x\text{ + \_\_\_\_\_}[/tex]
Let's find the number that will make the expression a perfect trinomial.
To find the number, apply the formula:
[tex]\text{new term = (}\frac{b}{2})^2[/tex]
From the expression:
b = 8
Hence, we have:
[tex](\frac{b}{2})^2=(\frac{8}{2})^2=(4)^2=16[/tex]
Therefore, the number that will make the expression a perfec squaret trinomial is 16 .
Hence, the trinomial is:
[tex]x^2+8x+16[/tex]
ANSWER:
16
