Answer :
Position and Velocity
If we are given the function of the position X(t) where t is the time, the velocity function v(t) is the first derivative of X(t).
The position of the particle is given by:
[tex]X(t)=t^2-6t+5[/tex]The velocity is calculated by finding the first derivative:
[tex]\begin{gathered} V(t)=X^{\prime}(t) \\ V(t)=(t^2-6t+5)^{\prime} \end{gathered}[/tex]Taking the derivative:
[tex]V(t)=2t-6[/tex]Now we need to find when the velocity is 0, so we equate the function to 0 and solve for t.
2t - 6 = 0
Adding 6:
2t = 6
Dividing by 2:
t = 3
Answer: (C) 3