Answered

is (x-2) a factor of y=-1(x^3-5x^2+6x-30)(x^2-16)

Answer :

Polynomials

We are factoring

[tex]y=-(x^3-5x^2+6x-30)(x^2-16)[/tex]

We know

[tex](x^2-16)=(x-4)(x+4)[/tex][tex]\begin{gathered} x^3-5x^2+6x-30=x^2(x-5)^{}+6(x-5) \\ =(x-5)(x^2+6) \end{gathered}[/tex]

Then

[tex]y=-(x-5)(x^2+6)(x^{}-4)(x+4)[/tex]

Then (x - 2) is not a factor of y

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