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Select the correct answer from each drop-down menu.Consider this polynomial equation.6(x – 3)(x^2 + 4)(x + 1) = 0Use the equation to complete this statement.The equation hassolutions. Its real solutions are I

Answer :

ANSWER:

The equation has 4 solutions.

Its real solutions are x =3 and x = 1

EXPLANATION:

Given:

[tex]6(x-3)(x^2+4)(x+1)=0[/tex]

To find how many solutions the equation has, we have:

The solution will be the values of x.

There are factors already, which are:

(x - 3) = 0

x² + 4 = 0

x + 1 = 0

Therefore, the solutions are:

x = 3

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