ANSWER
0.5m UP
EXPLANATION
Given:
Determine the value of x at 3m using Pythagorean Theorem
[tex]\begin{gathered} Hyp^2\text{ = Opp + Adj}^2 \\ 6^2\text{ = x}^2\text{ + 3}^2 \\ x^2\text{ = 36 - 9} \\ x\text{ = }\sqrt{27} \\ x\text{ = 5.2} \end{gathered}[/tex]Determine the value of x at 2m using Pythagorean Theorem
[tex]\begin{gathered} Hyp^2\text{ = Opp}^2\text{ + Adj}^2 \\ 6^2\text{ = x}^2\text{ + 2}^2 \\ x^2\text{ = 36 -4} \\ x\text{ = }\sqrt{32} \\ x\text{ = 5.7} \end{gathered}[/tex]The Difference
5.7 - 5.2 = 0.5 m
Hence, the ladder reach 0.5m farther up when the base of the ladder is 2 m from the wall than when it is 3 m from the wall
