Okay, here we have this:
Considering the provided information, we are going to replace in the function f(x)-g(x), with the given values of bounds:
Lower bound (x=4):
[tex]\begin{gathered} f(4)-g(4)=2.5e^{-0.04\cdot\: 4}-0.2\cdot\: 4-1.2 \\ =2.5e^{\mleft\{-0.16\mright\}}-0.8-1.2 \\ =2.5\cdot\frac{1}{e^{0.16}}-2 \\ \approx0.13 \end{gathered}[/tex]The first value on the right side of the table is the one we just got.
Average of the bounds (x=4.5):
[tex]\begin{gathered} f(4.5)-g(4.5)=2.5e^{-0.04\cdot\: 4.5}-0.2\cdot\: 4.5-1.2 \\ =2.5e^{\mleft\{-0.18\mright\}}-0.9-1.2 \\ =2.5\cdot\frac{1}{e^{0.18}}-2.1 \\ =-0.01 \end{gathered}[/tex]The second value on the right side of the table is the one we just got.
Upper bound:
[tex]\begin{gathered} f(5)-g(5)=2.5e^{-0.04\cdot\: 5}-0.2\cdot\: 5-1.2 \\ =2.5e^{\mleft\{-0.2\mright\}}-1-1.2 \\ =2.5\cdot\frac{1}{e^{0.2}}-2.2 \\ =-0.15 \end{gathered}[/tex]The third value on the right side of the table is the one we just got.