Note that we have the equations
[tex]4a+7b=11[/tex]
and
[tex]-4a-6b=-10[/tex]
If we add this two equations, we get
[tex]4a+7b\text{ +(-4a - 6b) = 4a-4a + 7b -6b = b = 11+(-10) = 1}[/tex]
So, we get b=1.
If we replace this in the first equation, we get
[tex]4a+7\text{ = 11}[/tex]
by subtracting 7 on both sides, we get
[tex]4a\text{ = 11-7 = 4}[/tex]
Finally, if we divide by 4 on both sides, we get
[tex]a=\frac{4}{4}=1[/tex]
So the solution to the equation is a=b=1
