The question can be interpreted as follows;
2 bowls contain 16 fish
Therefore, how many bowls would you need to hold 48 fish?
This means, the average in each bowl would be
[tex]\begin{gathered} \text{Average}=\frac{16}{2} \\ \text{Average}=8\text{ fish (per bowl)} \end{gathered}[/tex]Next step, you can now divide 48 fish by 8 fish to find out how many bowls of 8 fish in each bowl you would have.
[tex]\begin{gathered} \text{Number of bowls}=\frac{48}{8} \\ \text{Number of bowls}=6 \end{gathered}[/tex]A quicker and more straightforward method is simply to set up an equation using the values given as ratios. This is shown below;
[tex]\frac{16}{2}=\frac{48}{x}[/tex]Cross multiply and you'll have;
[tex]\begin{gathered} x=\frac{2\times48}{16} \\ x=\frac{48}{8} \\ x=6 \end{gathered}[/tex]Therefore;
ANSWER:
[tex]x=6[/tex]