From the graph v = (1,3) and w = ( 6 , -1)
the distance vw = d
[tex]\begin{gathered} d=\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ ^{} \end{gathered}[/tex][tex]d=\sqrt[]{(6-1)^2+(-1-3)^2}=\sqrt[]{5^2+4^2}=\sqrt[]{25+16}=\sqrt[]{41}[/tex][tex]\sqrt[]{41}=6.4[/tex]
So, vw = 6.4 to the nearest tenth
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