Let's begin by identifying key information given to us:
[tex]\begin{gathered} 12p+30+30w \\ We\text{ will factorise using the common factor of these numbers. We have:} \\ \text{6 is the highest common factor of 12 \& 30} \\ \Rightarrow6(2p+5+5w) \\ \text{We can further break this down to become:} \\ 5w=4w+w\Rightarrow6(2p+5+4w+w) \\ \Rightarrow6(4w+2p+_{}5+w) \end{gathered}[/tex]
Hence, the second option 6(4w + 2p + 5 + w) is the answer
