How many milliliters of 10.5 M HCl(aq) are needed to prepare 160.0 mL of 1.00 M HCl(aq)?V=mL

So,
We could use the following equation:
M1 and M2 represent the initial and final concentrations and V1 and V2 represent the initial and final volumes respectively.
Replacing our values:
Therefore, 15.2380mL are required.