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Ryan keeps his loose change in a milk jug. Thejug contains 25 pennies, 15 nickels, 15 dimes,and 5 quarters. If Ryan shakes out one coin,what is the probability the coin will NOT be adime?A 75%B 50%C 25%D 663%

Answer :

Given:

The number of pennies, p=25.

The number of nickels, n=15.

The number of dimes, d=15.

The number of quarters, q=5.

The total number of coins is,

[tex]N=25+15+15+5=60[/tex]

The probabilty the coin is a dime is,

[tex]P(d)=\frac{d}{N}=\frac{15}{60}=\frac{1}{4}[/tex]

The to

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