Here, we want to evaluate the factorial expression.
[tex]\frac{23!}{11(26-5)!}[/tex]
by definition,
[tex]\begin{gathered} n!\text{ = }n(n-1)(n-2)(n-3)\ldots3.2.1 \\ n!\text{ = }n(n-1)! \\ n!\text{ = }n(n-1)(n-2)! \end{gathered}[/tex][tex]\Rightarrow\frac{23!}{11(26-5)!}=\frac{23!}{11(21)!}=\frac{23\times22\times21!}{11\times21!}=\frac{23\times22}{11}=46[/tex]
Answer: 46
